Let the Balloon Rise

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 30799 Accepted Submission(s): 10110

Problem Description

Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.

This year, they decide to leave this lovely job to you.

Input

Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.

A test case with N = 0 terminates the input and this test case is not to be processed.

Output

For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.

Sample Input

      5 
green 
red 
blue 
red 
red 
3 
pink 
orange 
pink 
0 

Sample Output

      red 
pink 

　　直接使用map来映射，方便至极。

#include 
      
       #include 
       
        #include 
        using namespace std;int main(  ){	int N;	while( cin>> N, N )	{		string temp;		map< string, int > mp;		map< string, int >:: iterator it;		for( int i= 1; i<= N; ++i )		{			cin>> temp;			mp[temp]++;		}			int max= -1;			for( it= mp.begin(); it!= mp.end(); ++it )		{			if( max< it->second )			{				max= it->second;				temp= it->first;			}		}		cout<< temp<< endl;	}}

转载于:https://www.cnblogs.com/Lyush/archive/2011/07/31/2122762.html

你可能感兴趣的文章